I’ve been working…
Lmaddallnumbersanddivide
byofdatapoints
Medina
middlenumber
averageofmiddlenumbers
mode
appearsthemost
product
scorefrequency
I
quartile
thedataisbrokeninto4equalparts
denotedasQ1Q203,04
Q2isthemedian
04isthemaximum
STEPONEbreakthepointsinhalffindthemedian
STEPTWOfindthemedian
oflowerupperhalfQ2
STEPTHREE
QImedian
oflowerhalfand03median
ofupperhalf
STEPFOUR
Qtlargestvaluednumber
mean 26.2308
X 341
x 9323
Sx sn 5.61477
x n 5.3945
NC ofdataputs 3
Mint 19
Qi 21
Mediant 25
QI 31
Maxx 38
IQR 10
in
outlierapointthatis1.5timestheQRfromQ viseversaforQi
dataset
19,2121,2123,2425,2629,3032,3238,50
a
d
outlier
ndQR
19 21 23 as a 29 31 333s so so at 43 us 47 40 si so so so so 61 63 656769
46iscloserto50than38
so50istheoutlier
Q3 = 31
31 + (1:5 £ 10)
31 + 15
46