1 27 233How do we findthevolumeofsuchsolids Zwe can employ a similarriemannsum approach to find the volumeIf f is a function of twovariables and was continuous y LD yand non negative over R then the volume Rof the solid between f and region RisSf f x y d Aalso if f is continuous over R whose boundaryisnottoocomplicated then the double integralexistsCorollary if the boundary of R is a smooth curve or afinite collection ofsuch curves then the doubleintegralexistsLet f and g be functions defined on R andlet cbe a constant and if bothdoubleintegrals exist1 SS c f x y dA CSS f x y dAR R2 S f x y Ig x y dA fix y dA I g x y dA3 if R is composedof R and Ra thenIf 1 tI 4you can integrate SiSab f x y dx dythe followingby using iterated integrals fed fab fix y dx dycorollary this is the same as fab Sed f x y dy dxwe can write this more simply as fabfed fix y dydxthe doubleintegral can give us the volume under a surface